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anonymous
 one year ago
Algebra 1 help. Will give medal and fan!:)
anonymous
 one year ago
Algebra 1 help. Will give medal and fan!:)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.04. Esmeralda is graphing a polynomial function as a parabola. Before she begins graphing it, explain how to find the vertex. Make sure you include how to determine if it will be a maximum or minimum point. Use an example quadratic function to help you explain and provide its graph.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im sorry im not sure how to do this question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know anyone who does? Please it's my last one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0try asking people who have a higher number and a lot of fans

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i also suggest searching your question on google or youtube

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't have time to look for people like that. I just started today and I need to turn this in in an hour. I have tried to figure it out on my own and icant.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay well try this website http://mathbitsnotebook.com/Algebra1/Quadratics/QDVertexForm.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think you use the vertex form to find the vertex

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK well thanks. I'll try. You still get the medal and fan.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0aww thanks you didn't have to , and sorry i learned this a while away ago

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Graphing a Quadratic Function in Vertex Form: 1. Start with the function in vertex form: y = a(x  h)2 + k y = 3(x  2)2  4 2. Pull out the values for h and k. If necessary, rewrite the function so you can clearly see the h and k values. (h, k) is the vertex of the parabola. Plot the vertex. y = 3(x  2)2 + (4) h = 2; k = 4 Vertex: (2, 4) 3. The line x = h is the axis of symmetry. Draw the axis of symmetry. x = 2 is the axis of symmetry
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