anonymous
  • anonymous
Algebra 1 help. Will give medal and fan!:)
Algebra
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
4. Esmeralda is graphing a polynomial function as a parabola. Before she begins graphing it, explain how to find the vertex. Make sure you include how to determine if it will be a maximum or minimum point. Use an example quadratic function to help you explain and provide its graph.
anonymous
  • anonymous
@hl147 please help?
anonymous
  • anonymous
Im sorry im not sure how to do this question

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anonymous
  • anonymous
Do you know anyone who does? Please it's my last one
anonymous
  • anonymous
try asking people who have a higher number and a lot of fans
anonymous
  • anonymous
i also suggest searching your question on google or youtube
anonymous
  • anonymous
I don't have time to look for people like that. I just started today and I need to turn this in in an hour. I have tried to figure it out on my own and icant.
anonymous
  • anonymous
oh okay well try this website http://mathbitsnotebook.com/Algebra1/Quadratics/QDVertexForm.html
anonymous
  • anonymous
i think you use the vertex form to find the vertex
anonymous
  • anonymous
OK well thanks. I'll try. You still get the medal and fan.
anonymous
  • anonymous
aww thanks you didn't have to , and sorry i learned this a while away ago
anonymous
  • anonymous
Nah its fine lol
anonymous
  • anonymous
Graphing a Quadratic Function in Vertex Form: 1. Start with the function in vertex form: y = a(x - h)2 + k y = 3(x - 2)2 - 4 2. Pull out the values for h and k. If necessary, rewrite the function so you can clearly see the h and k values. (h, k) is the vertex of the parabola. Plot the vertex. y = 3(x - 2)2 + (-4) h = 2; k = -4 Vertex: (2, -4) 3. The line x = h is the axis of symmetry. Draw the axis of symmetry. x = 2 is the axis of symmetry
anonymous
  • anonymous
this is an example
anonymous
  • anonymous
Ok. Yeah i got it.
anonymous
  • anonymous
ok good

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