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AmTran_Bus

  • one year ago

Someone check this calc 2?

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  1. AmTran_Bus
    • one year ago
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  2. AmTran_Bus
    • one year ago
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    I said converges since I got a limit at 0?

  3. Haseeb96
    • one year ago
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    Correct

  4. freckles
    • one year ago
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    how did you get 0?

  5. freckles
    • one year ago
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    \[\lim_{n \rightarrow \infty}n(n-6)\] that looks like a product of really big numbers

  6. AmTran_Bus
    • one year ago
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    Did i mess up? let me try again...

  7. AmTran_Bus
    • one year ago
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    @Haseeb96 @freckles so am i right or not guess we can check on wolfram

  8. freckles
    • one year ago
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    the product of really big positive numbers is a really big positive number

  9. freckles
    • one year ago
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    not 0

  10. AmTran_Bus
    • one year ago
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    So the limit is infinity? I mean, as long as there is a limit it converges, right?

  11. freckles
    • one year ago
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    infinity or -infinity means it diverges

  12. Haseeb96
    • one year ago
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    if the limit is infinity then it will be divergence

  13. freckles
    • one year ago
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    infinity isn't a number just so you know it just means it gets really really big

  14. Haseeb96
    • one year ago
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    but @freckles he said limit is 0 so i said he is correct

  15. freckles
    • one year ago
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    why is the limit 0 @Haseeb96

  16. AmTran_Bus
    • one year ago
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    Ok. Well, thanks all. I need to go back and review I guess.

  17. freckles
    • one year ago
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    I'm pretty sure the product of really big positive numbers can not be 0

  18. freckles
    • one year ago
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    do you understand why it diverges @AmTran_Bus

  19. AmTran_Bus
    • one year ago
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    Yes, I understand if it is infinity it diverges. Thanks. But I need to solve the limit correctly.

  20. AmTran_Bus
    • one year ago
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    But I see what you are saying with that @freckles

  21. SolomonZelman
    • one year ago
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    \(a_n=n(n-6)\) \(\displaystyle \lim_{n\rightarrow\infty }n(n-6)\) \(\displaystyle \lim_{n\rightarrow\infty }n^2-6n\) diverges to positive inifinity.

  22. AmTran_Bus
    • one year ago
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    Thanks solomon

  23. SolomonZelman
    • one year ago
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    Sure.... everytime to see the sequence convergence, for any sequence \(A_n\) , take the limit of it as n approaches infinity

  24. freckles
    • one year ago
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    60(54)=? 100(94)=? 1000(994)=? 10000(9994)=? these products are getting super super big

  25. SolomonZelman
    • one year ago
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    And if sequence diverges, then (always!) the series diverges

  26. AmTran_Bus
    • one year ago
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    Yes. I super see that now. Thanks so much freckles. I think I understand it.

  27. AmTran_Bus
    • one year ago
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    Thanks solomonzelman

  28. SolomonZelman
    • one year ago
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    yw

  29. SolomonZelman
    • one year ago
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    ((that was my favorite section when I learned it, btw))

  30. SolomonZelman
    • one year ago
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    good luck, you will get an A I am sure... !

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