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anonymous

  • one year ago

Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 81 minus the quantity of y minus 3 squared divided by 144 = 1. Vertices: (4, 3), (-14, 3); Foci: (-20, 3), (10, 3) Vertices: (3, 7), (3, -17); Foci: (3, -17), (3, 7) Vertices: (7, 3), (-17, 3); Foci: (-17, 3), (7, 3) Vertices: (3, 4), (3, -14); Foci: (3, -20), (3, 10) @ganeshie8 @pooja195 @solomonzelman @zepdrix @paki @loser66 @luigi0210

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  1. anonymous
    • one year ago
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  2. zepdrix
    • one year ago
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    hey c:

  3. zepdrix
    • one year ago
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    |dw:1436471011114:dw|Since our x term is the positive one, it's telling us we're opening right and left.

  4. zepdrix
    • one year ago
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    But the 5 and -3 are telling us to shift this whole thing `5 left` and `3 up`.|dw:1436471197900:dw|

  5. zepdrix
    • one year ago
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    oh boy.. best graph ever -_-

  6. zepdrix
    • one year ago
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    so let's start by finding some vertices.. hmm

  7. zepdrix
    • one year ago
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    The "center" of our hyperbola has been shifted to (-5,3). To find our vertex on the right branch, let's `add a` to the x-coordinate. We just want to move a distance of `a to the right` to get to the vertex. Do you understand what your `a` and `b` values are?

  8. anonymous
    • one year ago
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    (3, 7), (3, -17) would this be our vertices? @zepdrix

  9. anonymous
    • one year ago
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    @zepdrix ???

  10. zepdrix
    • one year ago
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    I'm not sure how you came up with that one +_+ What are you a and b values?

  11. anonymous
    • one year ago
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    i was just taking a guess. i dont know what they are?

  12. anonymous
    • one year ago
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    @SolomonZelman @ganeshie8

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spraguer (Moderator)
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