anonymous
  • anonymous
the total value of a collection of dimes and nickels is $2.70. if the total number of coins is 39, how many of each coin is there?
Algebra
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
hold on im trying to figure it out
anonymous
  • anonymous
thanks
anonymous
  • anonymous
it is a pain

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More answers

anonymous
  • anonymous
yeaah lol
anonymous
  • anonymous
\[\large \sf d+n=39 \\\large \sf .1d+.05n=2.7\]
anonymous
  • anonymous
soooo, there is half a nickel??
anonymous
  • anonymous
15 dimes 24 nickels?
anonymous
  • anonymous
thanks man
anonymous
  • anonymous
Woah there, no direct answers. @.Gjallarhorn.
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
lets see.. 15 dimes is 1.50 24 nickels 1.20 addem and you get 2.70
anonymous
  • anonymous
i know im explaining
anonymous
  • anonymous
And the method you used to figure it out?
anonymous
  • anonymous
15 dimes and 24 nickels add up to 39 coins :)
anonymous
  • anonymous
That isn't a method, my friend :)
anonymous
  • anonymous
i just used guess and eliminate
anonymous
  • anonymous
and i got the answer and i explained why that was the answer by adding the values
anonymous
  • anonymous
And that's the problem. We're here to help the asker UNDERSTAND, which your method doesn't do. Your method doesn't work on anything but things like this. With such a small margin of answers, it's easy to guess around and get the answer.
anonymous
  • anonymous
I mean, have you ever had a teacher tell you, "Guess around till you get the answer"? /:
anonymous
  • anonymous
Number of dimes: x Number of nickels: (39-x) 10x + 5(39-x) = 270 (cents makes sense) 5x = 75 x = 15, the number of dimes. 24 Nickels checking.... 10*15+5*24 = 270cents or $2.70 THERE YA GO @bearclaw heres the source http://www.algebra.com/algebra/homework/word/coins/Word_Problems_With_Coins.faq.question.879243.html so your final answer is 15 dimes and 24 nickels, bearclaw. Have a nice day! :)

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