PLEASE HELP!! If the area of a rectangle is 16s2t and the length is 8st2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer. 2st 2 over the quantity s times t the quantity of 2 times s all over t t over the quantity 2 times s

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PLEASE HELP!! If the area of a rectangle is 16s2t and the length is 8st2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer. 2st 2 over the quantity s times t the quantity of 2 times s all over t t over the quantity 2 times s

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Area=Length*Width Width=Area/Length Area=16s^2t Width=8st^2 Width=16s^2t/8st^2 Width=2s/t

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