## anonymous one year ago If f(x) = 1 – x, which value is equivalent to |f(i)|? options are: A.0 B.1 C. √2 D. √-1

1. freckles

$|a+bi|=\sqrt{a^2+b^2}$

2. chrisdbest

B should be the closest

3. freckles

it actually isn't B

4. chrisdbest

Bcuz i = sqrt -1, and the absolut value of a negative number is a positive number

5. freckles

$f(i)=1-i \\ |f(i)|=|1-i|=?$

6. anonymous

sorry guys but im still in the blue here ahahah

7. chrisdbest

Oh so its A!!!

8. freckles

$|1-i|=\sqrt{1^2+1^2}=?$

9. chrisdbest

Cuz 1 - 1 = 0!

10. chrisdbest

11. freckles

or if you wanted to look at it as $\sqrt{1^2+(-1)^2} \text{ instead of } \sqrt{1^2+1^2}$

12. anonymous

ayyyy lmao

13. freckles

all I'm asking you to do is do the 1+1 underneath the radical

14. freckles

$|a+bi|=\sqrt{a^2+b^2} \ \\ \text{ and you have } \\ |1+-1i|=\sqrt{1^2+(-1)^2}=\sqrt{1^2+1^2}=?$ can you finish this ?

15. anonymous

OOOOOOOO THANKS MAN LMAO I DONT KNOW HOW I DIDNT SEE THAT ahha its √2

16. freckles

yep :)

17. chrisdbest

Dang I didn't even see that answer choice. I'm Dyslexic, I thought it said $\sqrt{21}$