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anonymous
 one year ago
PLEASE HELP!
John is choosing a password for his access to the internet. He decided not to use the digit 0 or the letter M. Each letter or number may be used more than once. How many passwords of 2 letters followed by 4 digits are possible?
anonymous
 one year ago
PLEASE HELP! John is choosing a password for his access to the internet. He decided not to use the digit 0 or the letter M. Each letter or number may be used more than once. How many passwords of 2 letters followed by 4 digits are possible?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is not simply 6 numbers multiplied...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know it has to do with factoids, but they never gave us anything this hard in the lesson.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First let's fill the first two blanks with the two letters. A letter can be used more than once. However, the letter M is not allowed. Excluding the M, how many letters are in the Latin alphabet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's an online course Im taking to escape the evil teacher at my school. Keystone Online. Otherwise, I go to Herberger Young Scholars Academy at ASU West.

muscrat123
 one year ago
Best ResponseYou've already chosen the best response.0and i also tagged u in another persons question. it is the same as urs i believe, but read all the comments b4 putting an answer. hope it helps :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes! OK so then since a letter may be repeated, how many ways are there of choosing two letters?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0125 letter combinations and 6561 number combos

Nurali
 one year ago
Best ResponseYou've already chosen the best response.0The choice for the no. of ways in which the first two letters can be chosen from available 25 letters = 25P2 = 600 And, the no. of ways in which the four digits can be chosen from available nine other digits = 9P2=72 Now, The no. of passwords possible are = 600 * 72 = 43200

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If the first position can be filled with any of the 25 letters, then there are 25 ways of performing this first action. Now for the second letter, also any of the 25 letters can be used, hence there are 25 ways of performing this second action. Then there are 25 X 25 ways of picking two letters.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i mean 625 letter combinations
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