• anonymous
Find an equation in standard form for the hyperbola with vertices at (0, ±6) and asymptotes at y = ±3 divided by 2.x. y squared over 36 minus x squared over 16 = 1 y squared over 4 minus x squared over 9 = 1 y squared over 36 minus x squared over 4 = 1 y squared over 16 minus x squared over 36 = 1 @ganeshie8 @dan815 @solomonzelman @luigi0210 @thomaster @nurali @eclipsedstar @acxbox22
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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