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Is there a picture that goes with this?
ok we know angle A equals angle C since 90-45=45 |dw:1436475407394:dw|
we also know length AB=length CB
|dw:1436475460289:dw| I chose to let them both be 1 and by Pythagorean theorem the hyp is sqrt(2)
can you find sin(A) cos(A) tan(A) csc(A) sec(A) cot(A)
recall soh cah toa
sin=opp/hyp cos=adj/hyp tan=opp/adj
would it be tan C ?
so we can also consider other angles too?
C is 45 deg tan(45)=opp/adj =1/1=1 so yes 1 is difference from 1/sqrt(2)
but there is also tan(A) to consider
which is actually the same thing as tan(C)
since both A and C are 45 deg
you also have the reciprocal functions to consider to
so many to name :p
so its tan a
do you have choices?
well yes tan(A) also works
but so does sec(A) and csc(A)
and if you can consider other angles then so does sec(C) and csc(C)
I sent the choices earlier there further up. and I would say tan C
I just see a triangle
tan(C) and tan(A) and sec(A) and csc(A) and sec(C) and csc(C) will all work
like that is none of them are equal to sin(A)
you can also so sin(B) and cos(B) and tan(B) and csc(B) and sec(B) and cot(B) can also work too