Use the given graph to determine the limit, if it exists. @amistre64 @phi @solomonzelman @jdoe0001 @paki

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@jdoe0001 please help

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well... the situation is the same as before really notice the left-sided limit, it ends up at -1 whilst the right-sided limit ends up at -4 so they don't meet, thus the double-sided limit does not exist
Find the derivative of f(x) = 8x + 4 at x = 9.
use the power rule keep in mind that derivative of a constant is 0 \(\bf \cfrac{d}{dx}[8x+4]\implies \cfrac{d}{dx}[8x]+\cfrac{d}{dx}[4]\)
so it would be 4? @jdoe0001
well. the derivative of 4, a constant is 0 what about the derivative of 8x? using the power rule you'd get?
it would be 8? @jdoe0001
yeap, is a constant, is 8 so that's the derivative f'(x) = 8 now if we set x = 9 the derivative or the function, doesn't change, still 8, since it's a constant
so it is 8? @jdoe0001
yeap
The position of an object at time t is given by s(t) = -9 - 3t. Find the instantaneous velocity at t = 8 by finding the derivative. @jdoe0001
hmm not very sure on that one if we were to take the derivative, is just -3 a constant, thus t = 8 will make no difference on the derivative but you may want to repost, since I'm not sure on that one
okay thank you so much @jdoe0001

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