John stands on the edge of a deck that is 40.0 m above the ground and throws a rock straight up that reaches a height of 15.0 m above the deck. What is the initial speed of the rock in m/s?
which i solved correctly and it is 17.1
Assuming the rock in the previous question misses the deck on the way down, how fast (in m/s) will the rock be moving when it hits the ground? @ybarrap @lightgrav

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i used the equation \[2as = V _{f}^{2} - V{i}^{2}\]

(or, you could start with v_i = 0, but watch the rock fall 55m

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