## anonymous one year ago A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle.

1. DanJS

It will be the product of the two...

2. DanJS

$l = \sqrt[3]{81} = 81^{1/3}$ $w = 3^{2/3} = [3^2]^{1/3} = 9^{1/3}$

3. DanJS

$A = l*w = 81^{1/3} * 9^{1/3} = [{81*9}]^{1/3} = 729^{1/3} = 9$

4. DanJS

just a bunch of power rules