## Falling_In_Katt one year ago Simplify the expression where possible. $(X ^{3}Y ^{2})^{4}$

1. condor34

4x^3y^2

2. campbell_st

the index law for power of a power is multiply the powers $(x^a)^b = x^{a \times b}$ so the power of 4 outside the brackets operates on both terms inside $x^{3 \times 4}y^{2 \times 4}$ just simplify it

3. Falling_In_Katt

$x ^{12}y ^{8}?$

4. campbell_st

that's correct