Jason has two bags with 6 tiles each. The tiles in each bag are shown below:
Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered 3 from the second bag?
1 over 36
1 over 12
2 over 12
2 over 6

- anonymous

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- muscrat123

r u trying

- anonymous

##### 1 Attachment

- anonymous

Yes

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## More answers

- muscrat123

ok good

- anonymous

@hotguy need ur help

- anonymous

@muscrat123 i took ur adivce

- muscrat123

and what is that?

- anonymous

That openstudyy is not for cheating its for help c:

- muscrat123

that is exactly right!!! im glad u realized and took my advice

- anonymous

c: yep and @hotguy u there? :/

- anonymous

@misssunshinexxoxo HELPPPPP XC

- anonymous

@muscrat123 would u be able to help :/

- muscrat123

maybe. need to read it first @wil476003

- anonymous

okiee

- anonymous

@manutd30

- anonymous

ANYONE HELP PLEASEEEEEEEE im on a timed test and need help

- anonymous

This isn't a graded test right?

- anonymous

nononon

- anonymous

Ok, good.

- anonymous

its for practice

- anonymous

do u know the answer? by any chance or how

- anonymous

Well what's the probability of getting a 2 out of the 6 tiles? And what's the probability of getting a 3 out of the 6 tiles?

- anonymous

Nope, it's not

- anonymous

hmmmm i know its over 12 doe right

- anonymous

Nope

- anonymous

no.... :c

- anonymous

the only possible answer is 1 over 36

- anonymous

@LegendarySadist

- anonymous

Multiply the probabilities \[\large \sf \frac{1}{6} \times \frac{1}{6}\]

- anonymous

2 over 6

- anonymous

yes? so my answer is 2 over 6

- anonymous

thats the part i usually get confused on

- anonymous

\[\large \sf \frac{1}{6} \times \frac{1}{6}~=~\frac{1 \times 1}{6 \times 6}\] @liana1026

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