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Falling_In_Katt

  • one year ago

Simplify the expression where possible. \[(-4x ^{2})^{2}\]

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  1. AbdullahM
    • one year ago
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    Hint: \(\sf\Large (a^b)^c = a^{b \times c}\)

  2. jdoe0001
    • one year ago
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    ditto

  3. Falling_In_Katt
    • one year ago
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    \[-4^{4}\]?

  4. DanJS
    • one year ago
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    \[[-4^1*x^2]^2\]

  5. Falling_In_Katt
    • one year ago
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    What? I'm confused.

  6. DanJS
    • one year ago
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    \[= (-4^1)^2*(x^2)^2\]

  7. AbdullahM
    • one year ago
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    Another hint: \(\sf\Large (xy)^z = x^{z} y^{z}\)

  8. DanJS
    • one year ago
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    @AbdullahM wrote the correct general power rules to remember... good luck

  9. AbdullahM
    • one year ago
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    (:

  10. Falling_In_Katt
    • one year ago
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    \[-4x ^{4}?\]

  11. jdoe0001
    • one year ago
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    \(\bf (-4x ^{2})^{2}\implies (-4^1x^{2})^2\implies (-4^1)^2(x^2)^2\implies -4^{1\cdot 2}x^{2\cdot 2}\implies -4^2x^4\)

  12. jim_thompson5910
    • one year ago
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    @Falling_In_Katt when you square the -4, it turns into (-4)^2 = (-4)*(-4) = +16 notice how it's positive and not negative

  13. Falling_In_Katt
    • one year ago
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    Ohhh Thank you!

  14. jim_thompson5910
    • one year ago
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    It's positive because two negatives multiply to a positive

  15. jdoe0001
    • one year ago
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    hmmm actually shold be positive yes

  16. jdoe0001
    • one year ago
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    \(\bf (-4x ^{2})^{2}\implies (-4^1x^{2})^2\implies (-4^1)^2(x^2)^2 \\ \quad \\ (-4)(-4)(x)^4\implies +16x^4\)

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