Simplify the expression where possible. \[(-4x ^{2})^{2}\]

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Simplify the expression where possible. \[(-4x ^{2})^{2}\]

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Hint: \(\sf\Large (a^b)^c = a^{b \times c}\)
ditto
\[-4^{4}\]?

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Other answers:

\[[-4^1*x^2]^2\]
What? I'm confused.
\[= (-4^1)^2*(x^2)^2\]
Another hint: \(\sf\Large (xy)^z = x^{z} y^{z}\)
@AbdullahM wrote the correct general power rules to remember... good luck
(:
\[-4x ^{4}?\]
\(\bf (-4x ^{2})^{2}\implies (-4^1x^{2})^2\implies (-4^1)^2(x^2)^2\implies -4^{1\cdot 2}x^{2\cdot 2}\implies -4^2x^4\)
@Falling_In_Katt when you square the -4, it turns into (-4)^2 = (-4)*(-4) = +16 notice how it's positive and not negative
Ohhh Thank you!
It's positive because two negatives multiply to a positive
hmmm actually shold be positive yes
\(\bf (-4x ^{2})^{2}\implies (-4^1x^{2})^2\implies (-4^1)^2(x^2)^2 \\ \quad \\ (-4)(-4)(x)^4\implies +16x^4\)

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