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zeesbrat3

  • one year ago

A particle moves with velocity function v(t) = 3t^2 − 4t + 1, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds.

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  1. Astrophysics
    • one year ago
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    Take the derivative and then plug in t = 3

  2. Astrophysics
    • one year ago
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    \[a(t) = \frac{ dv(t) }{ dt }\]

  3. zeesbrat3
    • one year ago
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    So \[6t-4\] \[18-4\] \[= 14\]

  4. Astrophysics
    • one year ago
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    Bingo m/s^2

  5. Astrophysics
    • one year ago
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    or ft/s^2

  6. zeesbrat3
    • one year ago
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    Thank you!

  7. Astrophysics
    • one year ago
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    Np

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