## zeesbrat3 one year ago A particle moves with velocity function v(t) = 3t^2 − 4t + 1, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds.

1. Astrophysics

Take the derivative and then plug in t = 3

2. Astrophysics

$a(t) = \frac{ dv(t) }{ dt }$

3. zeesbrat3

So $6t-4$ $18-4$ $= 14$

4. Astrophysics

Bingo m/s^2

5. Astrophysics

or ft/s^2

6. zeesbrat3

Thank you!

7. Astrophysics

Np