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  • briana.img
How would I go about solving this problem? Right Triangles and Trigonometry: Law of Sines and Law of Cosines
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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  • briana.img
dan815
  • dan815
|dw:1436489997103:dw|
dan815
  • dan815
use law of cosine

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dan815
  • dan815
if its a right triangle then the side would be 12^2+5^2 =13^2 however the angle opposite the misisng side is 41 which is more than 30 degrees and if it was 30 degrees the missing side would be 7.5 so we know for 41 degreees the missing side ha to be greater than that, so its definately not a right triangle, so we have to use law of COSine
briana.img
  • briana.img
@dan815 i used law of cosine and came out with the answer of 13.9737
briana.img
  • briana.img
@jim_thompson5910 plz help
jim_thompson5910
  • jim_thompson5910
Law of cosines c^2 = a^2 + b^2 - 2*a*b*cos(C) c^2 = 12^2+13^2-2*12*13*cos(41) c = ???
briana.img
  • briana.img
@jim_thompson5910 13.9737 ???
jim_thompson5910
  • jim_thompson5910
12^2+13^2-2*12*13*cos(41) = 77.5306109704951 sqrt(77.5306109704951) = 8.80514684548163
jim_thompson5910
  • jim_thompson5910
not sure how you got 13.9737
briana.img
  • briana.img
@jim_thompson5910 so how would i go about for the other angles??
jim_thompson5910
  • jim_thompson5910
by using the law of sines
jim_thompson5910
  • jim_thompson5910
sin(A)/a = sin(B)/b = sin(C)/c

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