How would I go about solving this problem? Right Triangles and Trigonometry: Law of Sines and Law of Cosines

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How would I go about solving this problem? Right Triangles and Trigonometry: Law of Sines and Law of Cosines

Mathematics
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use law of cosine

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Other answers:

if its a right triangle then the side would be 12^2+5^2 =13^2 however the angle opposite the misisng side is 41 which is more than 30 degrees and if it was 30 degrees the missing side would be 7.5 so we know for 41 degreees the missing side ha to be greater than that, so its definately not a right triangle, so we have to use law of COSine
@dan815 i used law of cosine and came out with the answer of 13.9737
Law of cosines c^2 = a^2 + b^2 - 2*a*b*cos(C) c^2 = 12^2+13^2-2*12*13*cos(41) c = ???
@jim_thompson5910 13.9737 ???
12^2+13^2-2*12*13*cos(41) = 77.5306109704951 sqrt(77.5306109704951) = 8.80514684548163
not sure how you got 13.9737
@jim_thompson5910 so how would i go about for the other angles??
by using the law of sines
sin(A)/a = sin(B)/b = sin(C)/c

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