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Study_together
 one year ago
Best ResponseYou've already chosen the best response.0@TheSmartOne can help you. I have no clue how to do this

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3What are we solving for x, or y or both, use your trig ratios.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3dw:1436505609850:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3What ratio can we use to find the x, dw:1436505727553:dw

Welp
 one year ago
Best ResponseYou've already chosen the best response.1I'm trying to solve for both x and y. "What ratio can we use to find the x, " Tan X=\[6\sqrt{3} ?\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Yeah tan is good! So we have \[\tan \theta = \frac{ opp }{ adj } = \frac{ 18 }{ x }\] \[x = \frac{ 18 }{ \tan \theta } = \frac{ 18 }{ \tan(31) }\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3After you have x, you can find y using Pythagorean or using the ratios :)

Welp
 one year ago
Best ResponseYou've already chosen the best response.1I don't know how to do those with square roots. I have no idea how to stop the square root symbol on my calculator.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3You shouldn't have square root?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3dw:1436519818790:dw that's the square root symbol, what are you trying to do?

Welp
 one year ago
Best ResponseYou've already chosen the best response.1Nevermind. Y=\[3\sqrt{38}\]?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3\[\sin \theta = \frac{ opp }{ hyp } = \frac{ 18 }{ y } \implies y = \frac{ 18 }{ \sin(31) } \]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3You should also consider your answers, hypotenuse is the longest side, would your answer really make sense?

Welp
 one year ago
Best ResponseYou've already chosen the best response.1\[18^{2} + 6\sqrt{3}^{2} 342 \sqrt{342}= 3\sqrt{38}\] ^I was trying to solve it with the Pythagorean theorem. I don't know where I screwed up 18/sin(31)=34.9

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3\[a^2+b^2 = c^2 \implies 18^2 + (29.957...)^2 = y^2 \implies y = \sqrt{18^2+(29.957...)^2} =34.948...\]
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