## -Welp- one year ago How do I solve this? http://i.imgur.com/UOhG3B8.png (trig help)

1. Study_together

@TheSmartOne can help you. I have no clue how to do this

2. Astrophysics

What are we solving for x, or y or both, use your trig ratios.

3. Astrophysics

|dw:1436505609850:dw|

4. Astrophysics

What ratio can we use to find the x, |dw:1436505727553:dw|

5. -Welp-

I'm trying to solve for both x and y. "What ratio can we use to find the x, " Tan X=$6\sqrt{3} ?$

6. Astrophysics

Yeah tan is good! So we have $\tan \theta = \frac{ opp }{ adj } = \frac{ 18 }{ x }$ $x = \frac{ 18 }{ \tan \theta } = \frac{ 18 }{ \tan(31) }$

7. Astrophysics

After you have x, you can find y using Pythagorean or using the ratios :)

8. -Welp-

I don't know how to do those with square roots. I have no idea how to stop the square root symbol on my calculator.

9. Astrophysics

You shouldn't have square root?

10. Astrophysics

|dw:1436519818790:dw| that's the square root symbol, what are you trying to do?

11. -Welp-

Nevermind. Y=$3\sqrt{38}$?

12. Astrophysics

$\sin \theta = \frac{ opp }{ hyp } = \frac{ 18 }{ y } \implies y = \frac{ 18 }{ \sin(31) }$

13. Astrophysics

14. -Welp-

$18^{2} + 6\sqrt{3}^{2} 342 \sqrt{342}= 3\sqrt{38}$ ^I was trying to solve it with the Pythagorean theorem. I don't know where I screwed up 18/sin(31)=34.9

15. Astrophysics

$a^2+b^2 = c^2 \implies 18^2 + (29.957...)^2 = y^2 \implies y = \sqrt{18^2+(29.957...)^2} =34.948...$