-Welp-
  • -Welp-
How do I solve this? http://i.imgur.com/UOhG3B8.png (trig help)
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Study_together
  • Study_together
@TheSmartOne can help you. I have no clue how to do this
Astrophysics
  • Astrophysics
What are we solving for x, or y or both, use your trig ratios.
Astrophysics
  • Astrophysics
|dw:1436505609850:dw|

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Astrophysics
  • Astrophysics
What ratio can we use to find the x, |dw:1436505727553:dw|
-Welp-
  • -Welp-
I'm trying to solve for both x and y. "What ratio can we use to find the x, " Tan X=\[6\sqrt{3} ?\]
Astrophysics
  • Astrophysics
Yeah tan is good! So we have \[\tan \theta = \frac{ opp }{ adj } = \frac{ 18 }{ x }\] \[x = \frac{ 18 }{ \tan \theta } = \frac{ 18 }{ \tan(31) }\]
Astrophysics
  • Astrophysics
After you have x, you can find y using Pythagorean or using the ratios :)
-Welp-
  • -Welp-
I don't know how to do those with square roots. I have no idea how to stop the square root symbol on my calculator.
Astrophysics
  • Astrophysics
You shouldn't have square root?
Astrophysics
  • Astrophysics
|dw:1436519818790:dw| that's the square root symbol, what are you trying to do?
-Welp-
  • -Welp-
Nevermind. Y=\[3\sqrt{38}\]?
Astrophysics
  • Astrophysics
\[\sin \theta = \frac{ opp }{ hyp } = \frac{ 18 }{ y } \implies y = \frac{ 18 }{ \sin(31) } \]
Astrophysics
  • Astrophysics
You should also consider your answers, hypotenuse is the longest side, would your answer really make sense?
-Welp-
  • -Welp-
\[18^{2} + 6\sqrt{3}^{2} 342 \sqrt{342}= 3\sqrt{38}\] ^I was trying to solve it with the Pythagorean theorem. I don't know where I screwed up 18/sin(31)=34.9
Astrophysics
  • Astrophysics
\[a^2+b^2 = c^2 \implies 18^2 + (29.957...)^2 = y^2 \implies y = \sqrt{18^2+(29.957...)^2} =34.948...\]

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