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briana.img

  • one year ago

How to find the angle measure of T?

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  1. briana.img
    • one year ago
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    I have no idea how to solve this since there's no other angle measure

  2. anonymous
    • one year ago
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    Try the law of cosines. Do you know it?

  3. wolf1728
    • one year ago
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    Here is the Law of Cosines

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  4. briana.img
    • one year ago
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    @wolf1728 are you sure thats it? i thought it was a^2=b^2+c^2-2bc cosa ???

  5. anonymous
    • one year ago
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    In your problem, let the three sides be t=7, r=11, s=10. Then the law of cosines becomes\[t ^{2}=r ^{2}+s ^{2}-2rs \cos \left( T \right)\]

  6. wolf1728
    • one year ago
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    ospreytriple's equation is better to use because itis written in terms of r, s and t

  7. briana.img
    • one year ago
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    @ospreytriple would i just plug in the numbers from the triangle???

  8. anonymous
    • one year ago
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    Rearranging, you get\[T=\cos ^{-1}\left(\frac{ r ^{2} +s ^{2}-t ^{2}}{ 2rs }\right)\]

  9. briana.img
    • one year ago
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    @ospreytriple i'm really confused on how i would get a real answer out of that equation :(

  10. anonymous
    • one year ago
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    just plug in the lengths of sides r, s, & t from the triangle.

  11. briana.img
    • one year ago
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    @ospreytriple oh okay that's what i was wondering lmao

  12. anonymous
    • one year ago
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    What do you get for an answer?

  13. briana.img
    • one year ago
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    @ospreytriple 45.57

  14. anonymous
    • one year ago
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    Not what I get. You want to try it again?

  15. briana.img
    • one year ago
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    @ospreytriple i got 63.25 :(

  16. briana.img
    • one year ago
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    @ospreytriple i got 63.25 :(

  17. briana.img
    • one year ago
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    @ospreytriple T=10? r=7? s=11?

  18. anonymous
    • one year ago
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    No. t=10. You are trying to find angle T.

  19. wolf1728
    • one year ago
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    briana r^2 = 121 s^2 = 100 t^2 = 49 r^2 + s^2 -t^2 = 172 agreed?

  20. wolf1728
    • one year ago
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    I think having 2 people explain things to a third gets a bit confusing good luck briana and osprey :-)

  21. briana.img
    • one year ago
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    @ospreytriple i listed those numbers because those are the ones you substitute in, right??

  22. anonymous
    • one year ago
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    Ok. Evaluate the above equation for T by using the values of r, s, & t from the triangle.

  23. briana.img
    • one year ago
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    @ospreytriple i know but i'm just asking if those are the numbers i use ??? like those are the correct ones for the substitution

  24. anonymous
    • one year ago
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    I believe those are the side lengths from the triangle, yes.

  25. anonymous
    • one year ago
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    \[T=\cos ^{-1}\left( \frac{ 11^{2}+10^{2} -7^{2}}{ 2\left( 11 \right)\left( 10 \right) } \right)\]

  26. briana.img
    • one year ago
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    @ospreytriple yeah i jsut did that and my answer came out to be 63.25 again

  27. anonymous
    • one year ago
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    What do you get for the value of the numerator?

  28. briana.img
    • one year ago
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    @ospreytriple 70

  29. anonymous
    • one year ago
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    Not quite.\[11^{2}+10^{2}-7^{1}=121+100-49= ?\]

  30. anonymous
    • one year ago
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    Should be 7^2. Sorry.

  31. briana.img
    • one year ago
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    @ospreytriple oh oops 172

  32. anonymous
    • one year ago
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    Great. Now the denominator is\[2\left( 11 \right)\left( 10 \right)=?\]

  33. briana.img
    • one year ago
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    @ospreytriple 220

  34. anonymous
    • one year ago
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    Terrific so\[T=\cos ^{-1}\left( \frac{ 172 }{ 220 } \right)=?\]

  35. briana.img
    • one year ago
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    @ospreytriple the calculator i'm using says 63.25???

  36. briana.img
    • one year ago
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    @ospreytriple wait nevermind 38.64

  37. anonymous
    • one year ago
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    Now you got it. Good job.

  38. briana.img
    • one year ago
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    @ospreytriple sorry fro taking so long :( this unit is really messing me up

  39. anonymous
    • one year ago
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    You're welcome. Those pesky calculators :)

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