briana.img
  • briana.img
FInd the measure of angle C
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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briana.img
  • briana.img
I've tried it twice and the second time i got 12.51400
briana.img
  • briana.img
I have fone \[a^2=13^2+17^2-2(13)(17)\cos47\]
briana.img
  • briana.img
done*

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More answers

anonymous
  • anonymous
For this one, use the sine law. Do you know it?
briana.img
  • briana.img
@ospreytriple yeah hold on let me try it out
briana.img
  • briana.img
@ospreytriple 10sinB=17sin47???
anonymous
  • anonymous
Shouldn't it be 13, not 10?
briana.img
  • briana.img
@ospreytriple oh yeah sorry about that 13sinb=17sin4
anonymous
  • anonymous
OK. The way I'm used to using the sine law is as follows:\[\frac{ \sin \left( A \right) }{ a } =\frac{ \sin \left( B \right) }{ b }\]. Is this the way you have it?
briana.img
  • briana.img
@ospreytriple yeah i did that but you have to rearange to the way i had it and then do s\[sinb=\frac{ 17\sin47 }{ 13 }\]
anonymous
  • anonymous
I think there's an error in the rearranging. You have \[\frac{ \sin \left( B \right) }{ b }=\frac{ \sin \left( C \right) }{ c }\]To isolate sin(C) you would multiply both sides of the equation by c, giving\[\frac{ c \sin \left( B \right) }{ b }=\sin \left( C \right)\]Make sense?
briana.img
  • briana.img
@ospreytriple yeah
anonymous
  • anonymous
OK. So solve\[\sin \left( C \right)=\frac{ 17 \sin \left( 47 \right) }{ 13 }\]
briana.img
  • briana.img
@ospreytriple calculator got 1.27436702
anonymous
  • anonymous
What do you get for sin(47)?
briana.img
  • briana.img
@ospreytriple 0.7313
anonymous
  • anonymous
Good. Multiply that number by 17 and divide that answer by 13. What do you get?
briana.img
  • briana.img
@ospreytriple 0.956315
anonymous
  • anonymous
Excellent. Now evaluate \[C=\sin ^{-1}\left( 0.956315 \right)\]
briana.img
  • briana.img
@ospreytriple calculator is getting 73.00200763 but doesnt seem right at all
anonymous
  • anonymous
That's what I get. Is that one of your choices?
briana.img
  • briana.img
@ospreytriple oh nvm it is i was looking at the wrong problem lmao thank you!!
anonymous
  • anonymous
Yayyy! Just remember to be very careful how you use your calculator.

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