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anonymous
 one year ago
A graph of 2 functions is shown below.
anonymous
 one year ago
A graph of 2 functions is shown below.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which of the following is an approximate solution for f(x) = g(x)? A)x = 1 B)x = −1 C)x = −4 D)x = 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you are being asked this: "find the x values of the coordinates were the two graphs intersect "

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2you see you have to graphs right? one is a line, the other some kind of curve

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2at some some point the cross

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2actually it looks like they touch somewhere and cross somewhere do you see where?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2what is the x coordinate of the point where they cross, the one on the right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2if that is confusing let me know

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2because that is what you need to answer the question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a lit confusing, im not good at this...

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2i filled in the point what are the coordinates of that point ?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2or actually all you need is the x coordinate it is sitting right there underneath that point

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so thats the answer?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2that is all \[\color\magenta\heartsuit\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2wasn't that hard, was it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you lol no i see now and is easy
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