Graph the function in the interval from 0 to 2pi

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Graph the function in the interval from 0 to 2pi

Mathematics
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ehh idk how to do this one :( sorry
Ok thanks :)
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Are my options
we can rewrite your function as follows: \[y - 2 = 2\cos \left( {x + \frac{\pi }{6}} \right)\]
how do we graph it from there?
now I make this traslation of the x,y-plane: \[\left\{ \begin{gathered} Y = y - 2 \hfill \\ X = x + \frac{\pi }{6} \hfill \\ \end{gathered} \right.\] where X and Y are the new coordinates
using those coordintes, we can rewrite your function as below: \[Y = 2\cos X\]
am I right?
I think so. Which graph would work best?
the graph of the function: \[Y = 2\cos X\] is: |dw:1436508552379:dw|
Do you think graph B is the best fit?
now we have to refer that graphys to our old coordinates x,y
graphic*
in order to do that, we note that the origin of the X,Y plane is located at: X=0, and Y=0 so substituting into our transformation formulas, we get: \[\left\{ \begin{gathered} 0 = y - 2 \hfill \\ 0 = x + \frac{\pi }{6} \hfill \\ \end{gathered} \right. \Rightarrow \left\{ \begin{gathered} y = 2 \hfill \\ x = - \frac{\pi }{6} \hfill \\ \end{gathered} \right.\]
How do i graph that
so here is the requested graph: |dw:1436508973906:dw|
i dont have a graph that matches that
more precisely, we have: |dw:1436509257926:dw|
yes, you have, please look at the third option
now you have to neglect the X,Y reference system of my drawing. What do you get?

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