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anonymous

  • one year ago

[Help] Simplify: 2x^4 - 5x^3 - 24x^2 + 13x + 10 over 2x^2 + x +1

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  1. anonymous
    • one year ago
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    \[(2x^4-5x^3-24x^2+13x+10)\div(2x^2+x-1)\]

  2. alekos
    • one year ago
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    we have to use long division for a polynomial. Have you ever done this before?

  3. anonymous
    • one year ago
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    Yes. I'm quite surprised because in the end I only have 10x left.

  4. anonymous
    • one year ago
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    My answer is \[x^2-3x-10+\frac{ 10x }{2x^2+x-1}\]

  5. alekos
    • one year ago
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    it should end up as a quadratic ax^2 +bx + c with a possible remainder

  6. alekos
    • one year ago
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    yeah that looks right but give me five minutes and i'll check your answer

  7. anonymous
    • one year ago
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    Are we allowed to have a variable of 10x in the remainder? It's my first time to encounter such an equation. I usually end up with a constant/divisor. Instead of a value with a variable/divisor.

  8. alekos
    • one year ago
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    yes, you're right its normally just a constant but let me get back to you

  9. anonymous
    • one year ago
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    Okay, sure thing.

  10. alekos
    • one year ago
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    I get 20x on the numerator of the remainder

  11. alekos
    • one year ago
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    let me double check my ans

  12. anonymous
    • one year ago
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    Oops...I'm sorry. I meant 20x, not 10x. Just a type.

  13. alekos
    • one year ago
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    OK so you're right!

  14. anonymous
    • one year ago
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    an "x" in the numerator is all right?

  15. alekos
    • one year ago
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    it sure is

  16. Michele_Laino
    • one year ago
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    I confirm that your answer is right! @JustinSpeedster

  17. anonymous
    • one year ago
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    Okay, thanks a lot guys. :)

  18. alekos
    • one year ago
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    hey thanks Michele

  19. Michele_Laino
    • one year ago
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    :) @alekos

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