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anonymous
 one year ago
[Help] Simplify: 2x^4  5x^3  24x^2 + 13x + 10 over 2x^2 + x +1
anonymous
 one year ago
[Help] Simplify: 2x^4  5x^3  24x^2 + 13x + 10 over 2x^2 + x +1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(2x^45x^324x^2+13x+10)\div(2x^2+x1)\]

alekos
 one year ago
Best ResponseYou've already chosen the best response.1we have to use long division for a polynomial. Have you ever done this before?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. I'm quite surprised because in the end I only have 10x left.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My answer is \[x^23x10+\frac{ 10x }{2x^2+x1}\]

alekos
 one year ago
Best ResponseYou've already chosen the best response.1it should end up as a quadratic ax^2 +bx + c with a possible remainder

alekos
 one year ago
Best ResponseYou've already chosen the best response.1yeah that looks right but give me five minutes and i'll check your answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are we allowed to have a variable of 10x in the remainder? It's my first time to encounter such an equation. I usually end up with a constant/divisor. Instead of a value with a variable/divisor.

alekos
 one year ago
Best ResponseYou've already chosen the best response.1yes, you're right its normally just a constant but let me get back to you

alekos
 one year ago
Best ResponseYou've already chosen the best response.1I get 20x on the numerator of the remainder

alekos
 one year ago
Best ResponseYou've already chosen the best response.1let me double check my ans

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oops...I'm sorry. I meant 20x, not 10x. Just a type.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0an "x" in the numerator is all right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I confirm that your answer is right! @JustinSpeedster

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, thanks a lot guys. :)
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