## anonymous one year ago I need help with this problem Graph y-2=-1/3(x+3)^2 and find the following I have already made my graph and found the vertex, y-intercept, Max value, axis of symmetry. But I cant figure out how to calculate the x-intercept.

1. anonymous

Vertex:-3,2 Max:2 Axis of Symmetry: -3 y-intercept: (0,-1)

2. phi

the x-intercept means y = 0 so we can replace y with 0 in your equation to start with: $y-2=-\frac{1}{3} (x+3)^2 \\ 0-2=-\frac{1}{3} (x+3)^2 \\ -2=-\frac{1}{3} (x+3)^2$ I would multiply both sides by -3 to get $-3 \cdot -2=-3 \cdot -\frac{1}{3}\cdot (x+3)^2 \\ 6= (x+3)^2$ or $(x+3)^2 = 6$ I would take the square root of both sides as the next step.

3. anonymous

Thank you, phi!