A community for students.
Here's the question you clicked on:
 0 viewing
butterflydreamer
 one year ago
SIMPLE HARMONIC MOTION QUESTION  Please help me LOL. I completely forgot how to solve these types of questions :(
A ship needs 10m of water to pass down a channel safely. At low tide, the channel is 9m deep and at high tide it is 12m deep. Low tide is at 10 a.m and high tide at 5pm.
Assume that the tidal motion is simple harmonic.
period= 14hrs and amplitude = 1.5m
**At what time can the ship safely proceed before midnight?
butterflydreamer
 one year ago
SIMPLE HARMONIC MOTION QUESTION  Please help me LOL. I completely forgot how to solve these types of questions :( A ship needs 10m of water to pass down a channel safely. At low tide, the channel is 9m deep and at high tide it is 12m deep. Low tide is at 10 a.m and high tide at 5pm. Assume that the tidal motion is simple harmonic. period= 14hrs and amplitude = 1.5m **At what time can the ship safely proceed before midnight?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the first two qs show that the 2nd derivative = w^2 x differentiate twice n then manipulate to get into that form

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0Would this be the equation to use? \[x = 1.5 \cos (\frac{ \pi }{ 7 } + \alpha) + 10.5\] Then let t = 0 , x = 9 so... \[9 = 10.5 + 1.5\cos \alpha\] \[1.5 = 1.5 \cos \alpha\] \[\cos \alpha = 1\] \[\alpha = \pi\] let x = 10 (because.. the ship needs 10m of water?) \[10 = 1.5 \cos (\pi t /7 + \pi) + 10.5\] \[0.5 = 1.5 \cos (\pi t/7 + \pi) \] \[\frac{ 1 }{ 3} = \cos (\pi t/7 + \pi) \] \[\cos ^{1} (1/3) = \frac{ \pi t }{ 7 } + \pi \]

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0\[\cos ^{1}(\frac{ 1 }{ 3 }) + \pi = \frac{ \pi t }{ 7 } + \pi\] \[\frac{ \pi t }{ 7 } = \cos ^{1} (\frac{ 1 }{ 3 }) \] \[t = \frac{ 7\cos ^{1}(\frac{ 1 }{ 3 }) }{ \pi }\]

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0right? xD going out on a limb right now.

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0so my final answer is 12:45 pm and 9:15 pm but it doesn't feel correct :/

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0*** 12:44pm and 9:15 am
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.