Which describes the graph of the polynomial function f(x) = (x – 2)(x – 4)(x + 1)? A. It falls to the left and rises to the right. B. It rises to the left and falls to the right. C. It rises to the left and to the right. D. It falls to the left and to the right.

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Which describes the graph of the polynomial function f(x) = (x – 2)(x – 4)(x + 1)? A. It falls to the left and rises to the right. B. It rises to the left and falls to the right. C. It rises to the left and to the right. D. It falls to the left and to the right.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Really need help guys :(
do you know what it would look if you sketched it out? :)
mmmm not really :(

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Other answers:

okaay, well... immediately just by looking at your function, you should know that it is a "cubic" curve since there are three values for x... (like if you were to expand your brackets, you'd get x^3 ) \[f(x) = (x-2) ( x -4) ( x + 1) \] So first step is to identify whether your cubic curve would be positive or negative. So if you expanded the brackets, would you get \[x^3 or x ^{-3}\]
ahhhh ok i see now
|dw:1436534121953:dw|
Also, it is important to find your x-intercepts :) So \[y = (x -2) (x-4) (x+1)\] And we know x-intercepts occur at y= 0 \[(x - 2) ( x- 4) (x+1) = 0 \] Therefore, x-intercepts would be ?
mmmm i dont i know exactly how to calculate the answer correctly
it's basically like this: x - 2 = 0 , so x = ? x - 4 = 0 , therefore x = ? x + 1 = 0 , so x = ?
by the looks of it they would be 0?
not quite... |dw:1436534488742:dw|
no wait i see now, that would be 2
yessss :) so we do the same thing for the other parts: x - 2 = 0 x = 2 (this is one of the x-intercepts ) x -4 = 0 x = 4 (2nd x-intercept) x + 1 = 0 x = -1 (3rd x-intercept) Therefore our x-intercepts are at: (2,0) (4,0) and (-1,0) Plot it out on a graph and we have these three points: also note how your cubic is positive because: |dw:1436534745095:dw| |dw:1436534674543:dw|
So based on the drawing, you should be able to see which direction the curve goes :) Hint: look at the direction of the arrow head of your curve |dw:1436534911001:dw|
so the answer should be A?
yaass ^_^
Yay i learned :D
:) woohoooo~
Thx alot

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