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Pandemonium
 one year ago
Which describes the graph of the polynomial function
f(x) = (x – 2)(x – 4)(x + 1)?
A. It falls to the left and rises to the right.
B. It rises to the left and falls to the right.
C. It rises to the left and to the right.
D. It falls to the left and to the right.
Pandemonium
 one year ago
Which describes the graph of the polynomial function f(x) = (x – 2)(x – 4)(x + 1)? A. It falls to the left and rises to the right. B. It rises to the left and falls to the right. C. It rises to the left and to the right. D. It falls to the left and to the right.

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Pandemonium
 one year ago
Best ResponseYou've already chosen the best response.0Really need help guys :(

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1do you know what it would look if you sketched it out? :)

Pandemonium
 one year ago
Best ResponseYou've already chosen the best response.0mmmm not really :(

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1okaay, well... immediately just by looking at your function, you should know that it is a "cubic" curve since there are three values for x... (like if you were to expand your brackets, you'd get x^3 ) \[f(x) = (x2) ( x 4) ( x + 1) \] So first step is to identify whether your cubic curve would be positive or negative. So if you expanded the brackets, would you get \[x^3 or x ^{3}\]

Pandemonium
 one year ago
Best ResponseYou've already chosen the best response.0ahhhh ok i see now

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436534121953:dw

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1Also, it is important to find your xintercepts :) So \[y = (x 2) (x4) (x+1)\] And we know xintercepts occur at y= 0 \[(x  2) ( x 4) (x+1) = 0 \] Therefore, xintercepts would be ?

Pandemonium
 one year ago
Best ResponseYou've already chosen the best response.0mmmm i dont i know exactly how to calculate the answer correctly

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1it's basically like this: x  2 = 0 , so x = ? x  4 = 0 , therefore x = ? x + 1 = 0 , so x = ?

Pandemonium
 one year ago
Best ResponseYou've already chosen the best response.0by the looks of it they would be 0?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1not quite... dw:1436534488742:dw

Pandemonium
 one year ago
Best ResponseYou've already chosen the best response.0no wait i see now, that would be 2

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1yessss :) so we do the same thing for the other parts: x  2 = 0 x = 2 (this is one of the xintercepts ) x 4 = 0 x = 4 (2nd xintercept) x + 1 = 0 x = 1 (3rd xintercept) Therefore our xintercepts are at: (2,0) (4,0) and (1,0) Plot it out on a graph and we have these three points: also note how your cubic is positive because: dw:1436534745095:dw dw:1436534674543:dw

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1So based on the drawing, you should be able to see which direction the curve goes :) Hint: look at the direction of the arrow head of your curve dw:1436534911001:dw

Pandemonium
 one year ago
Best ResponseYou've already chosen the best response.0so the answer should be A?
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