anonymous
  • anonymous
Find the derivative of f(x) = 5x + 9 at x = 2.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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butterflydreamer
  • butterflydreamer
To differentiate f(x) = 5x + 9 , the 9 is a constant. When you differentiate a constant, you get 0. So |dw:1436539169374:dw|
Melodious
  • Melodious
@nairz it is factor theorm right?
anonymous
  • anonymous
5x Also, what does the dash you put after the "(5x)" mean?

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Melodious
  • Melodious
can we do like substituting x with 2?
welshfella
  • welshfella
the dash mean the derivative of x use the rule for algebraic differentiation y = a x^n y' = an x^(n-1)
welshfella
  • welshfella
* dash means the derivative of f(x)
Melodious
  • Melodious
can i know whether i told is right?
anonymous
  • anonymous
I don't knnow @Melodious
Melodious
  • Melodious
pls which grade maths is this?
anonymous
  • anonymous
High school
welshfella
  • welshfella
- you substitute 2 after you have found the derivative
Melodious
  • Melodious
ninth grade?
anonymous
  • anonymous
@Melodious most likely 11-12 grade
Melodious
  • Melodious
@welshfella that was what i was asking from the beginning
butterflydreamer
  • butterflydreamer
yeah @welshfella is correct :) the dash just means derivative of.
Melodious
  • Melodious
@nairz i studied in ninth grade
Melodious
  • Melodious
the same topic
anonymous
  • anonymous
Ok. Well I don't know how to find n
Melodious
  • Melodious
n?
butterflydreamer
  • butterflydreamer
if we differentiate 5x, we don't get 5x :) |dw:1436539684365:dw|
anonymous
  • anonymous
n is 1 or -1?
butterflydreamer
  • butterflydreamer
positive
anonymous
  • anonymous
ok.
anonymous
  • anonymous
So 5x^0
anonymous
  • anonymous
or 1
welshfella
  • welshfella
x^0 = 1
butterflydreamer
  • butterflydreamer
5x^0 = 5 times x^0 = 5 times 1 = 5
anonymous
  • anonymous
so 5
welshfella
  • welshfella
so 5x^0 = ?
anonymous
  • anonymous
but if we take it's first derivative then it becomes only 5,then where to put the value of x?
butterflydreamer
  • butterflydreamer
i have no idea..:/
welshfella
  • welshfella
nowhere the values is 5
anonymous
  • anonymous
then what is the meaning of value at x=2?
welshfella
  • welshfella
f'(x) = 5 the graph will be a horizontal line so the values will be 5 whatever value x is
anonymous
  • anonymous
so is it 5 or 10?
welshfella
  • welshfella
|dw:1436539994984:dw|
butterflydreamer
  • butterflydreamer
it can't be 10... f ' (x) = 5 so it's just 5
anonymous
  • anonymous
OK
welshfella
  • welshfella
so f'(2) = 5
welshfella
  • welshfella
sorry that should be f'(x) on the vertical axis:-
welshfella
  • welshfella
|dw:1436540140306:dw|
butterflydreamer
  • butterflydreamer
yaaa :) So because it is a horizontal line , at ANY value of x, f'(x) = 5 ^-^

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