anonymous
  • anonymous
express sin 60 - sin 20 as a product Any ideas of how to start it? lol
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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welshfella
  • welshfella
there are some identities for sums and differences of sines and cosines as products they;ll be up on the web. i think sin A - sin B = 2 sin(A+B) cos(A- B) ---- ----- 2 2 but i'm not sure
anonymous
  • anonymous
I am using a different identity but how would you do it with that identity? @welshfella I am not finding a formula like that either lol
welshfella
  • welshfella
http://www.clarku.edu/~djoyce/trig/identities.html

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anonymous
  • anonymous
@welshfella we havent learned those identities in class however
welshfella
  • welshfella
mine was wrong its 2 cos (A+B) sin (a-B) -- -- 2 2
anonymous
  • anonymous
@welshfella anything else that would work with it?
welshfella
  • welshfella
well i suppose you can do this sin 40 = sin ( 2*20) = 2 sin 20 cos 20 sin 40 - sin 20 = 2 sin 20 cos 20 - sin 20 = sin 20 (2 cos 20 - 1)
welshfella
  • welshfella
ohh - im going crazy - its sin 60 !!
anonymous
  • anonymous
This question I swear XD This is the formula I think is right to use
anonymous
  • anonymous
The second one
welshfella
  • welshfella
yes - thats the one i mentioned last
anonymous
  • anonymous
So the way you just did it is how its done?
anonymous
  • anonymous
Is this right how I did it?
welshfella
  • welshfella
yes put A = 60 and B = 20 and simplify 2 cos (60 + 20) sin (60 - 20) ------ ------- 2 2
welshfella
  • welshfella
yes you got it
welshfella
  • welshfella
2 cos 40 sin 20

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