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vera_ewing
 one year ago
If the Ka of a conjugate acid is known, which other parameter can be determined?
A. Ka of the strong base
B. Ka of the strong acid
C. Kb of the weak acid
D. Kb of the weak base
vera_ewing
 one year ago
If the Ka of a conjugate acid is known, which other parameter can be determined? A. Ka of the strong base B. Ka of the strong acid C. Kb of the weak acid D. Kb of the weak base

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vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0@JoannaBlackwelder A or B?

thadyoung
 one year ago
Best ResponseYou've already chosen the best response.2What do you think? It's only one answer.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0When an acid is deprotonated or dontates a proton, that is \(\sf H^+ \) the remainder is called conjugate base. Typically, a strong acid's conjugate base is relatively stable, which means it is a weak one. Now, the same kind of concept applies in terms of conjugate acid.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0D is correct becouse the conjugate acid comes from base .with base you will use Kb not Ka

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1I don't think the answer is d... Remember this that the Kw=(Ka)(Kb) given the known Ka of the conjugate weak acid we can take it and find the Kb of the strong conjugate base like this Kw/Ka=Kb

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are correct , but there is nothing mensioned bout Kb, in this question, of strong base .it just mensioned kb of weak base

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Yeah kW = Ka x Kb I always get mixed up with the terminology.. "The Ka of a conjugate acid is known" If you know Ka you can get Kb that's for sure. If it's a strong base high Kb it will want that proton badly, I think it would produce a weak conjugate acid w Low Ka. I guess we don't know whether the base was strong of weak to begin with..

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Ok so why isn't it D?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0from my understanding whether you are given a \(\sf K_a~or~K_b \) it provides you the information of the other. The a and b are just an assignment for acid and base specifically. An acid's relative strength or weakness provide an information about it's conjugate base. Similarly, a conjugate acid will provide you the relative strength strength or weakness of the base. I think this problem is more about the terminology rather than the qualitative (strong or weak) or quantitative aspect of acidbase. So, if we have to choose from the options provided only considering the assignment of an "a" and "b", then we are looking for a description of base, and the best that will fit is base with a measurement of "b." I would like to read other reasoning if what I provided isn't good to answer the problem.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0That is to say that I agree with photon dude

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you have NH3 as a bas . NH4 will be it is conjugate acid .so if I know the Ka of NH4 I will apply Kw=Ka ×Kb . Ka will be for NH4 becouse it is acid (conjugate acid) while Kb for NH3 becouse its base. NH 3 is a weak base so the answer is (Kb of the weak base)
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