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anonymous

  • one year ago

Find 2p ^2 + 3p - 4 less - 2p ^2 - 3p + 4.

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  1. marihelenh
    • one year ago
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    Same thing but now with subtraction. You will take 2p^2-(-2p^2) and 3p-(-3p) and -4-4.

  2. marihelenh
    • one year ago
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    Subtracting a negative number is the same as adding it, so you can 2p^2+2p^2 and 3p+3p.

  3. mathstudent55
    • one year ago
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    \((2p^2 + 3p - 4) - (-2p^2 - 3p + 4) =\) You need to subtract the polynomials above. The first step is to rewrite the first polynomial without parentheses since those parentheses are not needed. \(= 2p^2 + 3p - 4 - (-2p^2 - 3p + 4) \) The next step is to deal with the parentheses around the second polynomial. We need to get rid of those parentheses.

  4. marihelenh
    • one year ago
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    When you add them, you should get 4p^2+6p-8.

  5. anonymous
    • one year ago
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    so 4p^2 and 6p and -8?

  6. anonymous
    • one year ago
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    thanks for the help

  7. mathstudent55
    • one year ago
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    Since there is a negative sign to the left of the parentheses, in order to get rid of the parentheses, you distribute the negative sign to each each term inside the parentheses. What ends up happening is that every sign inside the parentheses changes. \(= 2p^2 + 3p - 4 - (-2p^2 - 3p + 4)\) \(= 2p^2 + 3p - 4 + 2p^2 + 3p - 4\) Now that the parentheses are taken care of, you just combine like terms like we did before. \(= 2p^2 + 2p^2 + 3p + 3p - 4 - 4\) \(= 4p^2 + 6p + - 8\)

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