## Falling_In_Katt one year ago I^15 =

1. welshfella

i^2 = -1 , i^3 = ii and i^4 = 1

2. welshfella

* i^3 = -i

3. welshfella

i^12 = (i^4)^3 = 1 i^15 = i^4 * i^3

4. welshfella

* last line is i^15 = i^12 * i^3

5. Falling_In_Katt

I'm so confused.

6. welshfella

i^2 = -1 thats by definition right?

7. Falling_In_Katt

wait...would it be -i

8. marihelenh

1 raised to any power is always going to be 1. You could right it out as 1*1*1*1*1*1*1*1*1*1*1*1*1*1*1=1 if you wanted, but it will always be 1.

9. welshfella

yes -i is correct

10. Falling_In_Katt

Oh thank you!

11. Michele_Laino

we have: ${i^2} = - 1 \Rightarrow {i^{14}} = {\left( {{i^2}} \right)^7} = {\left( { - 1} \right)^7} = - 1 \Rightarrow {i^{15}} = {i^{14}}i = ...?$

12. welshfella

i assumed this was an i - in the question - but it looks like 1 lol!