Falling_In_Katt
  • Falling_In_Katt
I^15 =
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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welshfella
  • welshfella
i^2 = -1 , i^3 = ii and i^4 = 1
welshfella
  • welshfella
* i^3 = -i
welshfella
  • welshfella
i^12 = (i^4)^3 = 1 i^15 = i^4 * i^3

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welshfella
  • welshfella
* last line is i^15 = i^12 * i^3
Falling_In_Katt
  • Falling_In_Katt
I'm so confused.
welshfella
  • welshfella
i^2 = -1 thats by definition right?
Falling_In_Katt
  • Falling_In_Katt
wait...would it be -i
marihelenh
  • marihelenh
1 raised to any power is always going to be 1. You could right it out as 1*1*1*1*1*1*1*1*1*1*1*1*1*1*1=1 if you wanted, but it will always be 1.
welshfella
  • welshfella
yes -i is correct
Falling_In_Katt
  • Falling_In_Katt
Oh thank you!
Michele_Laino
  • Michele_Laino
we have: \[{i^2} = - 1 \Rightarrow {i^{14}} = {\left( {{i^2}} \right)^7} = {\left( { - 1} \right)^7} = - 1 \Rightarrow {i^{15}} = {i^{14}}i = ...?\]
welshfella
  • welshfella
i assumed this was an i - in the question - but it looks like 1 lol!

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