## anonymous one year ago The curve $$y = \sqrt{x}$$, from $$x = 0$$ to $$x = 9$$ is rotated about the x-axis to form a solid, which is then rotated about the y-axis to form a larger solid. What is the volume of the larger solid? I know the answer is 1944π/5, but can someone help me get to this answer?

1. anonymous

Actually, I think I may have gotten it. Can someone confirm if this logic is correct? Doing this double rotation is equivalent to rotating $$y = 2\sqrt{x}$$ around the y-axis.

2. Empty

Yeah that sounds right to me.

3. anonymous

Thanks. Just had a moment of stupidity there.