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anonymous

  • one year ago

The curve \(y = \sqrt{x}\), from \(x = 0\) to \(x = 9\) is rotated about the x-axis to form a solid, which is then rotated about the y-axis to form a larger solid. What is the volume of the larger solid? I know the answer is 1944π/5, but can someone help me get to this answer?

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  1. anonymous
    • one year ago
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    Actually, I think I may have gotten it. Can someone confirm if this logic is correct? Doing this double rotation is equivalent to rotating \(y = 2\sqrt{x}\) around the y-axis.

  2. Empty
    • one year ago
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    Yeah that sounds right to me.

  3. anonymous
    • one year ago
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    Thanks. Just had a moment of stupidity there.

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spraguer (Moderator)
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