A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Find the limit of the function using cancellation techniques (6 + x) / x^4
Please explain.
anonymous
 one year ago
Find the limit of the function using cancellation techniques (6 + x) / x^4 Please explain.

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know how to do cancellation, but only with numerators that are factorable.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like Use cancellation techniques to evaluate limit as x approaches 1 of 2x squared minus x minus 3 divided by (x + 1). You can factor the numerator as (2x 3)(x + 1). After cancelling out the common factor of (x+1), the limit can be evaluated using direct substation. The limit is equal to 5

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0@hartnn can help ya (:

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2separate the numerator \(6/x^4 \) + \(x/x^4\) cancel out one x in the 2nd term

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why is 1 in the numerator?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, that went right over my head.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So wouldn't it be 0 as the limit?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2where does the x approach? x> 0 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know. I was taught to just to insert whatever number, in this case 0, in the factored equation.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2"in this case 0" you deduced that from the question, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah. Wait, wouldn't it not exist?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2" just to insert whatever number" is the worst way anyone can teach limits :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's virtual school. ..

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2if x approaches 0, the numerator is negative, the denominator is very very near to 0 hence the limit will approach infinity :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thats not an option...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2*** negative number /0 = infinity

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2what are the options? can yo post the screenshot of entire question and options?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2so they haven't introduced you to infinity yet... in that case, you can choose "Does Not Exist" as the answer. even though the limit exist and =  infinity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Exactly! It's basic math, but some websites say it would be 0, if and only if the x> infinity.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2when x> infinity, means x is a very large number then 1/x will be very small number hence, 1/x^3 and 1/x^4 will approach 0 hence you limit will be = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep. Thank you for the help! I really appreciated it. cx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It was that they did not exist. cx @hartnn
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.