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anonymous
 one year ago
Jesse has eight friends who have volunteered to help with a school fundraiser. Five are boys and three are girls. If he randomly selects 3 friends to help him, find each probability?
Probability of all boys or all girls
anonymous
 one year ago
Jesse has eight friends who have volunteered to help with a school fundraiser. Five are boys and three are girls. If he randomly selects 3 friends to help him, find each probability? Probability of all boys or all girls

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kropot72
 one year ago
Best ResponseYou've already chosen the best response.1The probability of choosing a boy on the first selection is 5/8. Having chosen a boy on the first selection, there are 4 boys out of a total of 7 friends remaining. Therefore the probability of choosing a boy on the second selection is 4/7. Having chosen boys on the first and second selections, there are 3 boys out of a total of 6 friends remaining. Therefore the probability of choosing a boy on the third selection is 3/6. \[\large P(all\ boys)=\frac{5\times4\times3}{8\times7\times6}=you\ can\ calculate\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay since the question is asking for all boys or all girls Do I do the same for the girls and add them together

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1The events 'all boys' and 'all girls' are mutually exclusive, therefore you need to calculate the probability of all girls (using the same reasoning as for all boys) and add the two values of probability.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got it It is 11/56 I have another question involving this problem it is asking for probability of at least 2 girls

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1You need to find the probability of exactly 2 girls. Then add that probability to the probability of all girls.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So 2 out of 8 + 3/8 Is 5/8

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1Not so. The probability of all girls is given by \[\large P(all\ girls)=\frac{3\times2\times1}{8\times7\times6}=you\ can\ calculate\] The probability of exactly 2 girls is given by \[\large P(2\ girls)=\frac{3C2\times5C1}{8C3}=\frac{3\times5}{56}=you\ can\ calculate\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so 1/56 plus 15/56 Is 16/56 simified is 4/14

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1And 4/14 simplified is 2/7.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have one more Probability of at least 1 boy It's exact of 1 boy plus Al Boys correct So 1/56 plus what?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1The probability of no boys is 1/56. Therefore the probability of at least 1 boy is given by \[\large P(at\ least\ 1\ boy)=11/56=you\ can\ calculate\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So 0/56? But my book says it 55/56

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1How did you get 0/56? 1  1/56 = 55/56

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh my bad I didn't do it correct Thank for helping me I appreciate it
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