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anonymous

  • one year ago

if 0 is less than or equal to t which is less than 2pi solve cos t + 1=2sin^2t any idea?

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  1. anonymous
    • one year ago
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    Do you have options?

  2. anonymous
    • one year ago
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    No all on our own

  3. anonymous
    • one year ago
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    cos(t) + 1 = 2 sin^2 t substitute , sin^2 t = 1 - cos^2 t from the identity sin^2 t + cos^2 t = 1 cos(t) + 1 = 2 ( 1 - cos^2 t ) distribute cos (t) + 1 = 2 - 2 cos^2 t 2 cos^2 (t) + cos (t) + 1 - 2 = 0 2 cos^2 (t) + cos (t) -1 = 0 factor (2 cos t - 1 ) ( cos t + 1 ) = 0

  4. anonymous
    • one year ago
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    @SurpriseBreeze i think you forgot to divide by two tho cuz look at number for equation

  5. anonymous
    • one year ago
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    four**

  6. anonymous
    • one year ago
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    I just googled it... sorry .-. I like your elephant! :D

  7. anonymous
    • one year ago
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    @SurpriseBreeze So is your answer right tho? and haha thanks

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spraguer (Moderator)
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