moazzam07
  • moazzam07
Craig wants to use an elevator to carry identical packages having the same weight. Each package weighs 4 pounds and Craig weighs 90 pounds. If the elevator can carry a maximum of 330 pounds at a time, which inequality shows the maximum number of packages, n, that Craig can carry with himself in the elevator if he is the only passenger? n ≥ 60 n ≤ 60 n ≤ 236 n ≥ 236
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
johnweldon1993
  • johnweldon1993
Okay so lets find an expression for the total weight in the elevator We have his weight (90) and the weight of each package (p) which is 4 pounds each...so (4p) So the total weight in the elevator at any given time is \[\large 90 + 4p\] Now...we know the elevator cannot handle more than 330 pounds...so we need the total weight to always be less than or equal to that So \[\large 90 + 4p \le 330\] And we just need to simplify that a bit and solve for 'p'
moazzam07
  • moazzam07
-4 from both sides?
johnweldon1993
  • johnweldon1993
Dont be afraid to tag me back here :) So if we have \[\large 90 + 4p \le 330\] our goal is to isolate the 'p' since that is what we are solving for So first...we see that 90 is being added to the 4p...so lets subtract 90 from both sides of our equation to cancel that out \[\large \cancel{90 - 90} + 4p \le 330 - 90\] Giving us \[\large 4p \le 240\] Now..we have a 4 being multiplied to the ''...so to cancel that out...we divide both sides of the equation by 4 \[\large \frac{\cancel{4}p}{\cancel{4}} \le \frac{240}{4}\] And we end up with?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

moazzam07
  • moazzam07
p < 240
moazzam07
  • moazzam07
or equal to
johnweldon1993
  • johnweldon1993
Not quite...remember up there we needed to divide the 240 by 4
moazzam07
  • moazzam07
yes
moazzam07
  • moazzam07
60?
johnweldon1993
  • johnweldon1993
There we go So we have \(\large p \le 60\)
johnweldon1993
  • johnweldon1993
Or in your case 'n' ...sorry should have kept the variables the same
moazzam07
  • moazzam07
ah ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.