The pair of values below is from a direct variation. Find the missing number. (2,5) and (4,y)

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The pair of values below is from a direct variation. Find the missing number. (2,5) and (4,y)

Algebra
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Direct variation is form \(y = kx\), where k is some unknown number. So first, we need to find k. We are given known point \((2,5)\), so plug that; \(5 = k(2)\quad\Longrightarrow\quad k = \dfrac52\) Now we know k, we can solve for y from point (4, y); \(y = \dfrac{5}{2}(4)=~?\)
Y= 10 simple :/

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