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\[\large v(t) = \dfrac{\mathrm d }{\mathrm dt}~s(t)\]Right?

You just need to evaluate \(v(2)\)

If I evaluate the formula at t=-2 I just get -14

*2

How did you get -14?
Can you find derivative of -2 - 6t ?

I don't think I know how to find derivatives properly.

When it says derivative, I think derived from t equaling 2 and the formula -2 -6t. -2-6*(2)=-14

I don't think that's how it works though.

(d/-2d)-(d/-2d)=0

I don't have a teacher

Can you tell me what you got, then we can work it out.

So you are self-taught?

Probably online school :) ^^

yes

If someone could offer me the answer to this question, I would be glad to discuss how it was found