position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the derivative.

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\[\large v(t) = \dfrac{\mathrm d }{\mathrm dt}~s(t)\]Right?

You just need to evaluate \(v(2)\)

If I evaluate the formula at t=-2 I just get -14

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