factor the polynomial correctly c^2-64

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factor the polynomial correctly c^2-64

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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What do you think you should do first?
i really have no clue on this one

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Other answers:

Do you know the difference of squares?
i heard of it just forgot what it meant
Trying to factor as a Difference of Squares : Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B) Proof : (A+B) • (A-B) = A^2 - AB + BA - B^2 = A^2 - AB + AB - B^2 = A^2 - B^2
Make sense?
not really
Where?
c^2 is a perfect square 64 is a perfect square
Therefore, we apply the difference of squares.
but how do we factor them
Check : 64 is the square of 8 Check : c2 is the square of c1 Factorization is : (c + 8) • (c - 8)
See? It's simple as that when I apply the difference of squares rules.
so you basically just take the square root of eat number
yes..
refer to one of my first responses for the rules.
so your answer will be c-8
no..
I literally spoonfed you the answer.
A^2 - B^2 can be factored into (A+B) • (A-B)
so... (c-8)(c+8)
Yes.
thank you

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