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mitu12

  • one year ago

factor the polynomial correctly c^2-64

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  1. mitu12
    • one year ago
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    @Aureyliant

  2. anonymous
    • one year ago
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    What do you think you should do first?

  3. mitu12
    • one year ago
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    i really have no clue on this one

  4. anonymous
    • one year ago
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    Do you know the difference of squares?

  5. mitu12
    • one year ago
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    i heard of it just forgot what it meant

  6. anonymous
    • one year ago
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    Trying to factor as a Difference of Squares : Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B) Proof : (A+B) • (A-B) = A^2 - AB + BA - B^2 = A^2 - AB + AB - B^2 = A^2 - B^2

  7. anonymous
    • one year ago
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    Make sense?

  8. mitu12
    • one year ago
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    not really

  9. anonymous
    • one year ago
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    Where?

  10. anonymous
    • one year ago
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    c^2 is a perfect square 64 is a perfect square

  11. anonymous
    • one year ago
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    Therefore, we apply the difference of squares.

  12. mitu12
    • one year ago
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    but how do we factor them

  13. anonymous
    • one year ago
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    Check : 64 is the square of 8 Check : c2 is the square of c1 Factorization is : (c + 8) • (c - 8)

  14. anonymous
    • one year ago
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    See? It's simple as that when I apply the difference of squares rules.

  15. mitu12
    • one year ago
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    so you basically just take the square root of eat number

  16. anonymous
    • one year ago
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    yes..

  17. anonymous
    • one year ago
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    refer to one of my first responses for the rules.

  18. mitu12
    • one year ago
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    so your answer will be c-8

  19. anonymous
    • one year ago
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    no..

  20. anonymous
    • one year ago
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    I literally spoonfed you the answer.

  21. anonymous
    • one year ago
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    A^2 - B^2 can be factored into (A+B) • (A-B)

  22. mitu12
    • one year ago
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    so... (c-8)(c+8)

  23. anonymous
    • one year ago
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    Yes.

  24. mitu12
    • one year ago
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    thank you

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