mitu12
  • mitu12
factor the polynomial correctly c^2-64
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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mitu12
  • mitu12
@Aureyliant
anonymous
  • anonymous
What do you think you should do first?
mitu12
  • mitu12
i really have no clue on this one

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More answers

anonymous
  • anonymous
Do you know the difference of squares?
mitu12
  • mitu12
i heard of it just forgot what it meant
anonymous
  • anonymous
Trying to factor as a Difference of Squares : Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B) Proof : (A+B) • (A-B) = A^2 - AB + BA - B^2 = A^2 - AB + AB - B^2 = A^2 - B^2
anonymous
  • anonymous
Make sense?
mitu12
  • mitu12
not really
anonymous
  • anonymous
Where?
anonymous
  • anonymous
c^2 is a perfect square 64 is a perfect square
anonymous
  • anonymous
Therefore, we apply the difference of squares.
mitu12
  • mitu12
but how do we factor them
anonymous
  • anonymous
Check : 64 is the square of 8 Check : c2 is the square of c1 Factorization is : (c + 8) • (c - 8)
anonymous
  • anonymous
See? It's simple as that when I apply the difference of squares rules.
mitu12
  • mitu12
so you basically just take the square root of eat number
anonymous
  • anonymous
yes..
anonymous
  • anonymous
refer to one of my first responses for the rules.
mitu12
  • mitu12
so your answer will be c-8
anonymous
  • anonymous
no..
anonymous
  • anonymous
I literally spoonfed you the answer.
anonymous
  • anonymous
A^2 - B^2 can be factored into (A+B) • (A-B)
mitu12
  • mitu12
so... (c-8)(c+8)
anonymous
  • anonymous
Yes.
mitu12
  • mitu12
thank you

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