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anonymous

  • one year ago

Let u = <-5, -3>, v = <-6, -1>. Find -3u + 5v. @hero @dan815 @nincompoop @mathstudent55 @wio @radar @undeadknight26

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    multiply both entries in \(u\) by \(-3\) multiply both entries in \(v\) by \(5\) then add

  3. anonymous
    • one year ago
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    huh? @misty1212

  4. misty1212
    • one year ago
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    i don't really know another way to say it

  5. misty1212
    • one year ago
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    u has two numbers right?

  6. anonymous
    • one year ago
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    can u show me? @misty1212

  7. misty1212
    • one year ago
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    multiply each of them by \(-3\)

  8. misty1212
    • one year ago
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    \[u=<-5,-3>\\ -3u=-3<-5,-3>=<15,9>\]

  9. misty1212
    • one year ago
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    in other words, multiply each entry by \(-3\)

  10. misty1212
    • one year ago
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    repeat to find \[5v=5<-6,-1>\]

  11. anonymous
    • one year ago
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    so its <-30,-5> @misty1212

  12. misty1212
    • one year ago
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    yes

  13. misty1212
    • one year ago
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    then add

  14. anonymous
    • one year ago
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    can u help me with another? @misty1212

  15. misty1212
    • one year ago
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    did you add them yet?

  16. anonymous
    • one year ago
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    yes i got <-15,4> @misty1212

  17. misty1212
    • one year ago
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    oops yes you are right sorry

  18. anonymous
    • one year ago
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    can u help me with another? @misty1212

  19. misty1212
    • one year ago
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    ok sure

  20. anonymous
    • one year ago
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    Find a • b. a = 4i + 3j, b = -4i + 4j -4 28 <-16, 12> <0, 7>

  21. misty1212
    • one year ago
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    is that a dot between them?

  22. anonymous
    • one year ago
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    i think it times

  23. misty1212
    • one year ago
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    i think it means the "dot product"

  24. misty1212
    • one year ago
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    \[<4,3>\cdot<-4,4>=4\times (-4)+3\times 4\]

  25. misty1212
    • one year ago
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    it is a number, not a vector

  26. misty1212
    • one year ago
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    \[-16+12=-4\] in other words

  27. anonymous
    • one year ago
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    Find the first six terms of the sequence. a1 = -7, an = 2 • an-1 -7, -14, -12, -10, -8, -6 0, 2, -14, -12, -10, -8 -7, -14, -28, -56, -112, -224 -14, -28, -56, -112, -224, -448

  28. anonymous
    • one year ago
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    @misty1212

  29. misty1212
    • one year ago
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    start with \(-7\)

  30. misty1212
    • one year ago
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    then multiply it by 2 to get the next number

  31. misty1212
    • one year ago
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    \[-7,-7\times 2,-7\times 2\times 2...\]

  32. misty1212
    • one year ago
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    so this one \[ -7, -14, -28, -56, -112, -224\]

  33. anonymous
    • one year ago
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    Find the standard form of the equation of the parabola with a focus at (0, 4) and a directrix at y = -4. y = 1 divided by 16x2 y2 = 16x y2 = 4x y = 1 divided by 4x2 @misty1212

  34. misty1212
    • one year ago
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    i would go with the first one want to check?

  35. misty1212
    • one year ago
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    http://www.wolframalpha.com/input/?i=parabola+y+%3D+1%2F16x%5E2

  36. misty1212
    • one year ago
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    yup looks good

  37. anonymous
    • one year ago
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    Find an explicit rule for the nth term of the sequence. 3, -12, 48, -192, ... an = 3 • 4n - 1 an = 3 • 4n + 1 an = 3 • (-4)n - 1 an = 3 • (-4)n @misty1212

  38. misty1212
    • one year ago
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    see how the signs change?

  39. anonymous
    • one year ago
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    yes by -4 @misty1212

  40. misty1212
    • one year ago
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    so only \[a_n=3(-4)^{n-1}\] makes any sense

  41. anonymous
    • one year ago
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    one last one? @misty1212

  42. misty1212
    • one year ago
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    kk

  43. anonymous
    • one year ago
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    Use graphs and tables to find the limit and identify any vertical asymptotes of the function.

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  44. misty1212
    • one year ago
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    ? vertical asymptote is where the denominator is zero, so \(x=5\)

  45. anonymous
    • one year ago
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    what is the limit @misty1212

  46. misty1212
    • one year ago
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    ooh i see

  47. misty1212
    • one year ago
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    limit is infinity \(\infty\)

  48. misty1212
    • one year ago
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    oh no oops

  49. misty1212
    • one year ago
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    try \(-\infty\)

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