## briana.img one year ago Someone help me with this problem? Very confused

1. briana.img

2. geerky42

Try use Pythagorean Theorem ( $$a^2+b^2=c^2$$ )?

3. briana.img

@geerky42 oh yeah forgot about that

4. geerky42

You have hypotenuse c=12, and leg a=4 or b=4 (let's go with b.) $$a^2+4^2=12^2$$ Here, we need to solve for a. $$a^2 = 12^2-4^2\\~\\a=\sqrt{12^2-4^2}$$

5. geerky42

Ok so you know what to do?

6. briana.img

@geerky42 i got 11.3! thanks!

7. geerky42

No problem