Can someone walk me through this problem? I always have a hard time with this.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Can someone walk me through this problem? I always have a hard time with this.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

@EmilyF03 excuse me?
I tried this but it didn't seem to work for me \[ 8^2=4^2+7^2-2(4)(7)\cos\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[ 8^2=4^2+7^2-2(4)(7)\cos(\theta)\]
isolate \(\cos(\theta)\) first
i ended up with -57=cosT but i don't think that's right
you should end up with -1 = -56cos(T) right?
dividing -56 both sides gives you 1/56 = cos(T)
don't i need to put it in cos^-1(-56) ?
cos(T) ? shouldn't it be cos(R) since you want to find m < R ?
@jim_thompson5910 ooh oops yepp i was just going off an example in my notes
ah, gotcha

Not the answer you are looking for?

Search for more explanations.

Ask your own question