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anonymous
 one year ago
Hi, I just joined cuz I need help with this problem.... thank you :*
Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses.
>f(x)=(x+a)/b
>g(x)=cx−d
Show your work to prove that the inverse of f(x) is g(x).
 Show your work to evaluate g(f(x)).
 Graph your two functions on a coordinate plane. Include a table of values for each function. Include 5 values for each function. Graph the line y = x on the same graph.
anonymous
 one year ago
Hi, I just joined cuz I need help with this problem.... thank you :* Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses. >f(x)=(x+a)/b >g(x)=cx−d Show your work to prove that the inverse of f(x) is g(x).  Show your work to evaluate g(f(x)).  Graph your two functions on a coordinate plane. Include a table of values for each function. Include 5 values for each function. Graph the line y = x on the same graph.

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ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2In the 1st equation write $$ y=\frac{x+a}{b} $$ Then replace x with y and y with x: $$ x=\frac{y+a}{b} $$ Then, solve for y. This is the inverse of \(f(x)\) You will immediately see what \(c\) and \(d\) should be.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\\\Huge\color{red}{❀}\cal\Huge\color{purple}{~Welcome~to ~OS}\Huge\color{red}{❀}\)\\ \(\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\huge\color{#ee82ee}{✿}\Huge\color{red}{❀}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What numbers should I use?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol thanks @GretaKnows

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm using a=5 and b=3.... that's ok right?

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2Did you check that the function you got was the inverse of the other

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is what i got soo far for part 1 and part 2... I'm not sure if its correct Part 1: f(x) = x + 5/3 (g(x) = (x+5)/3 Part 2: f(x) = 3x 5 Change f(x) for y: y = 3x 5 Switch the x and y: x =3y 5 Isolate the y by adding five to both sides: x + 5 =3y Divide both sides by 3: x+5=3y / 3 y=x+5/ 3 That’s how you get: y = x+5 / 3

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2When you graph f(x) and g(x) just choose 5 points for each and graph. Say x=3, 2, 0, 1, 2 Then graph y=x. You should see that f(x) is a mirror image of g(x) about the line y=x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait...... is part 1 and part 2 correct?????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But is it correct or not???

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2In your Part 1 Given \(a=5\) and \(b=3\) $$ f(x)=\frac{x+5}{3} $$ Not $$ f(x)=x+5/3 $$ Based on your original function. Be careful when dividing quantities, here we are dividing the entire quantity x+5 b 3, not just dividing 5 by 3. Make sense? In Part 2, your process is good, just remember the division issue I just mentioned. Redo it with this in mind.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i changed it to this..... f(x) = (x+5)/3????

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2yes and then redo your work using that equation for f(x)
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