## anonymous one year ago Hi, I just joined cuz I need help with this problem.... thank you :* Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses. ->f(x)=(x+a)/b ->g(x)=cx−d -Show your work to prove that the inverse of f(x) is g(x). - Show your work to evaluate g(f(x)). - Graph your two functions on a coordinate plane. Include a table of values for each function. Include 5 values for each function. Graph the line y = x on the same graph.

1. ybarrap

In the 1st equation write $$y=\frac{x+a}{b}$$ Then replace x with y and y with x: $$x=\frac{y+a}{b}$$ Then, solve for y. This is the inverse of $$f(x)$$ You will immediately see what $$c$$ and $$d$$ should be.

2. anonymous

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3. anonymous

What numbers should I use?

4. anonymous

lol thanks @GretaKnows

5. anonymous

I'm using a=5 and b=3.... that's ok right?

6. ybarrap

Did you check that the function you got was the inverse of the other

7. anonymous

This is what i got soo far for part 1 and part 2... I'm not sure if its correct Part 1: f(x) = x + 5/3 (g(x) = (x+5)/3 Part 2: f(x) = 3x -5 Change f(x) for y: y = 3x -5 Switch the x and y: x =3y -5 Isolate the y by adding five to both sides: x + 5 =3y Divide both sides by 3: x+5=3y / 3 y=x+5/ 3 That’s how you get: y = x+5 / 3

8. ybarrap

When you graph f(x) and g(x) just choose 5 points for each and graph. Say x=-3, -2, 0, 1, 2 Then graph y=x. You should see that f(x) is a mirror image of g(x) about the line y=x

9. anonymous

Wait...... is part 1 and part 2 correct?????

10. anonymous

But is it correct or not???

11. ybarrap

In your Part 1 Given $$a=5$$ and $$b=3$$ $$f(x)=\frac{x+5}{3}$$ Not $$f(x)=x+5/3$$ Based on your original function. Be careful when dividing quantities, here we are dividing the entire quantity x+5 b 3, not just dividing 5 by 3. Make sense? In Part 2, your process is good, just remember the division issue I just mentioned. Redo it with this in mind.

12. anonymous

so i changed it to this..... f(x) = (x+5)/3????

13. ybarrap

yes and then redo your work using that equation for f(x)