Please Help!! Suppose you have a box with 3 blue marbles, 2 red marbles, and 4 yellow marbles. You are going to pull out one marble, record its color, put it back in the box and draw another marble. What is the probability of pulling out a red marble followed by a blue marble? Be sure to reduce your answers. a. 6/81 = 2/27 b. 6/18 = 1/3 c. 5/9 d. 5/18

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Please Help!! Suppose you have a box with 3 blue marbles, 2 red marbles, and 4 yellow marbles. You are going to pull out one marble, record its color, put it back in the box and draw another marble. What is the probability of pulling out a red marble followed by a blue marble? Be sure to reduce your answers. a. 6/81 = 2/27 b. 6/18 = 1/3 c. 5/9 d. 5/18

Mathematics
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Which do you believe it could be?
Give me a second I have to find the answer I picked
These probabilities in the beginning could get tricky

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Other answers:

Hmm I can't find it
P(red) = 2/9 P(blue) = 3/9
P(redblue) = (2/9)(3/9) = 6/81 = 2/27
The multiplication rule says we need to find P(red) P(blue). P(red) = 2/9 P(blue) = 3/9 P(redblue) = (2/9)(3/9) = 6/81 = 2/27
Well, you first have to find the chance of getting a red marble, then multiply it by the chance of blue. 2/9*3/9=6/81=2/27
Well done all. :)

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