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anonymous

  • one year ago

Please Help!! Suppose you have a box with 3 blue marbles, 2 red marbles, and 4 yellow marbles. You are going to pull out one marble, record its color, put it back in the box and draw another marble. What is the probability of pulling out a red marble followed by a blue marble? Be sure to reduce your answers. a. 6/81 = 2/27 b. 6/18 = 1/3 c. 5/9 d. 5/18

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  1. misssunshinexxoxo
    • one year ago
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    Which do you believe it could be?

  2. anonymous
    • one year ago
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    Give me a second I have to find the answer I picked

  3. misssunshinexxoxo
    • one year ago
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    These probabilities in the beginning could get tricky

  4. anonymous
    • one year ago
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    Hmm I can't find it

  5. misssunshinexxoxo
    • one year ago
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    P(red) = 2/9 P(blue) = 3/9

  6. misssunshinexxoxo
    • one year ago
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    P(redblue) = (2/9)(3/9) = 6/81 = 2/27

  7. DecentNabeel
    • one year ago
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    The multiplication rule says we need to find P(red) P(blue). P(red) = 2/9 P(blue) = 3/9 P(redblue) = (2/9)(3/9) = 6/81 = 2/27

  8. anonymous
    • one year ago
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    Well, you first have to find the chance of getting a red marble, then multiply it by the chance of blue. 2/9*3/9=6/81=2/27

  9. misssunshinexxoxo
    • one year ago
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    Well done all. :)

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