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anonymous
 one year ago
For The Questions, a club has 10 members.
a. Find the number of different slates of 3 officers (list of president, vicepresident, and treasurer) that the club could have for officers.
b.Find the number of different slates of 4 officers (list of president, vicepresident, secretary, and treasurer) that the club could have for officers.
anonymous
 one year ago
For The Questions, a club has 10 members. a. Find the number of different slates of 3 officers (list of president, vicepresident, and treasurer) that the club could have for officers. b.Find the number of different slates of 4 officers (list of president, vicepresident, secretary, and treasurer) that the club could have for officers.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you studying combinations and permutations?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is this question a combination or a permutation? What do you think?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Remember that order doesn't matter in a combination but order does matter in a permutation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think the first one is a permutation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right you are. In fact, they both are. Can you see that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, because they have to be in a certain order, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, in the first question, you need to calculate\[_3 P_{10}\]Can you do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure how too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Actually, my notation was backwards. Sorry. The general equation for permutations is\[_{n}P_r=\frac{ n! }{\left( nr \right) !}\]And in the first question n=10 and r=3. Can you take it from here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 2 that's probably not correct is it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not quite. The equation becomes\[_{10}P_3=\frac{ 10! }{ 7! }\]If you write out the factorial multiplications you'll see that all the factors from 7 down will cancel.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Something like\[_{10}P_3=\frac{ 10\times9\times8\times7\times6\times5\times4\times3\times2\times1 }{ 7\times6\times5\times4\times3\times2\times1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0See. Everything from 7 down will cancel out leaving\[_{10}P_3=10\times9\times8=?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0720? that's what I got from the multiplication

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Excellent. Now try the second question by yourself. You need to calculate\[_{10}P_4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Terrific. Well done.
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