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anonymous
 one year ago
Which function has a domain of all real numbers?
A. Y=tanx
B. Y=cosx
C. Y=1/sinx
D. Y= secx
anonymous
 one year ago
Which function has a domain of all real numbers? A. Y=tanx B. Y=cosx C. Y=1/sinx D. Y= secx

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sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0is there a difference between B. and C. that I am not seeing?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0ok I am pretty sure the domain of y=cosx continues into infinity in both directions+, only the range is restricted from 1 to 1

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0y= tanx has aymptotes. I think y = secx has asymptotes and I also think that y= 1/sinx has asymptotes as well but Im a bit lazy to look them up.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Think of it this way:\[A. y=\tan x = \frac{ \sin x }{ \cos x }\]\[B. y=\cos x\]\[C. y=\frac{ 1 }{ \sin x }\]\[D. y=\sec x = \frac{ 1 }{ \cos x }\]In order for the domain to be the set of all real numbers, there must not exist a real number that would make any denominator equal to zero, as that would lead to an undefined value. Does that help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would be B, y=cosx?
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