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anonymous
 one year ago
Is it possible that P(A) = 17/3? Why or why not?
anonymous
 one year ago
Is it possible that P(A) = 17/3? Why or why not?

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geerky42
 one year ago
Best ResponseYou've already chosen the best response.4Are we talking about probability? Remember probability can only be in between 0 to 1. 0 means it's certain that it won't happen and 1 means it's certain that it will happens.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.4Is 17/3 in between 0 and 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know, this is a really confusing subject for me.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.4P(A) can only be in between 0 and 1, right? 0.5, 0, 1, 0.3324, or 0.65, etc. Can P(A) be equal to 17/3 ?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.4I would suggest you to convert 17/3 to decimal.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.4dw:1436583990368:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05.666667 this would be decimal form of it

geerky42
 one year ago
Best ResponseYou've already chosen the best response.4Yeah. And is that number in between 0 and 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, so it would be it because it is greater than 1, correct?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.4That's right. Therefore \(P(A)=17/3\) is invalid. Is that clear?
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