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anonymous

  • one year ago

Is it possible that P(A) = 17/3? Why or why not?

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  1. geerky42
    • one year ago
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    Are we talking about probability? Remember probability can only be in between 0 to 1. 0 means it's certain that it won't happen and 1 means it's certain that it will happens.

  2. geerky42
    • one year ago
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    Is 17/3 in between 0 and 1?

  3. anonymous
    • one year ago
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    I don't know, this is a really confusing subject for me.

  4. geerky42
    • one year ago
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    P(A) can only be in between 0 and 1, right? 0.5, 0, 1, 0.3324, or 0.65, etc. Can P(A) be equal to 17/3 ?

  5. geerky42
    • one year ago
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    I would suggest you to convert 17/3 to decimal.

  6. geerky42
    • one year ago
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    |dw:1436583990368:dw|

  7. anonymous
    • one year ago
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    5.666667 this would be decimal form of it

  8. geerky42
    • one year ago
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    Yeah. And is that number in between 0 and 1?

  9. anonymous
    • one year ago
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    No, so it would be it because it is greater than 1, correct?

  10. geerky42
    • one year ago
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    That's right. Therefore \(P(A)=17/3\) is invalid. Is that clear?

  11. anonymous
    • one year ago
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    Yes, it is. Thanks!

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