anonymous
  • anonymous
Is it possible that P(A) = 17/3? Why or why not?
Statistics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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geerky42
  • geerky42
Are we talking about probability? Remember probability can only be in between 0 to 1. 0 means it's certain that it won't happen and 1 means it's certain that it will happens.
geerky42
  • geerky42
Is 17/3 in between 0 and 1?
anonymous
  • anonymous
I don't know, this is a really confusing subject for me.

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geerky42
  • geerky42
P(A) can only be in between 0 and 1, right? 0.5, 0, 1, 0.3324, or 0.65, etc. Can P(A) be equal to 17/3 ?
geerky42
  • geerky42
I would suggest you to convert 17/3 to decimal.
geerky42
  • geerky42
|dw:1436583990368:dw|
anonymous
  • anonymous
5.666667 this would be decimal form of it
geerky42
  • geerky42
Yeah. And is that number in between 0 and 1?
anonymous
  • anonymous
No, so it would be it because it is greater than 1, correct?
geerky42
  • geerky42
That's right. Therefore \(P(A)=17/3\) is invalid. Is that clear?
anonymous
  • anonymous
Yes, it is. Thanks!

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