math

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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what have you tried?? (a) If first 3 MUST be answered, then how many are remaining, and how many out of them are to be answered?
oh so its 7c5
thats right :)

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(b) Atleast 4 out of 1st 5, so 2 cases : 4 out of first 4 and another 4 out of another 5 OR 5 out of 1st 5 and another 3 out of remaining 5
** 4 out of first 5 and another 4 out of another 5 OR 5 out of 1st 5 and another 3 out of remaining 5
2c1?
4 out of first 5 = 4C5 4 out of another 5 = 4C5 "4 out of first 5 and another 4 out of another 5" = 4C5 + 4C5 do it similarly for "5 out of 1st 5 and another 3 out of remaining 5"
sorry *** "4 out of first 5 and another 4 out of another 5" = 4C5 * 4C5
woah! 5C4, not 4C5 :P
Omg. 2c1 so far from 5c4. Darn.
Thank you so much @hartnn
so you got it? and welcome ^_^
yes yes =)

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