anonymous
  • anonymous
Simplifying Radicals a^1/2/a^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Haseeb96
  • Haseeb96
@taramgrant0543664 can you help this also ? LOL
UnkleRhaukus
  • UnkleRhaukus
\[\frac{a^n}{a^m}=a^{n-m}\]
xapproachesinfinity
  • xapproachesinfinity
You got to it first #unkle lol

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xapproachesinfinity
  • xapproachesinfinity
, about to post same thing
UnkleRhaukus
  • UnkleRhaukus
\[a^{-p}=\frac1{a^p}\]
UnkleRhaukus
  • UnkleRhaukus
what is your final answer @Heartz
jdoe0001
  • jdoe0001
hmm
jdoe0001
  • jdoe0001
\(\large \cfrac{a^n}{a^m}\implies a^{n-m}\qquad thus\qquad \cfrac{a^{\frac{1}{2}}}{a^2}\implies a^{\frac{1}{2}-2}\implies a^{\square ?}\)
Jacob902
  • Jacob902
a^3/2
jdoe0001
  • jdoe0001
well... notice,the "2" is negative though
jdoe0001
  • jdoe0001
\(\large { \cfrac{a^n}{a^m}\implies a^{n-m}\qquad thus\qquad \cfrac{a^{\frac{1}{2}}}{a^2}\implies a^{\frac{1}{2}-2}\qquad \begin{cases} 2=\cfrac{4}{2} \end{cases}\qquad thus \\ \quad \\ a^{\frac{1}{2}-2}\implies a^{\frac{1}{2}-\frac{4}{2}}\implies a^{\square ?} }\)

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