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anonymous
 one year ago
math
anonymous
 one year ago
math

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did they come up with that "*" portion?

moazzam07
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand the Png you have attached

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The * portion is the last step in integrating the given problem

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3***** \[\large\int\limits_0^s\frac{\mathrm ds}{\sqrt{12s+0.02s^2}}=\int\limits_0^t\mathrm dt\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0whats the original question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The one that @UnkleRhaukus wrote

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0oh, i thought those integrals were derived from some differential equation...

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3Let \(u = \sqrt{12s+0.02s^2}\) \(\mathrm du = (\cdots)\mathrm ds\)
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