anonymous
  • anonymous
math
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
How did they come up with that "*" portion?
moazzam07
  • moazzam07
i dont understand the Png you have attached
anonymous
  • anonymous
The * portion is the last step in integrating the given problem

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anonymous
  • anonymous
its 12 s
UnkleRhaukus
  • UnkleRhaukus
***** \[\large\int\limits_0^s\frac{\mathrm ds}{\sqrt{12s+0.02s^2}}=\int\limits_0^t\mathrm dt\]
anonymous
  • anonymous
yes =)
hartnn
  • hartnn
whats the original question?
anonymous
  • anonymous
The one that @UnkleRhaukus wrote
hartnn
  • hartnn
oh, i thought those integrals were derived from some differential equation...
UnkleRhaukus
  • UnkleRhaukus
Let \(u = \sqrt{12s+0.02s^2}\) \(\mathrm du = (\cdots)\mathrm ds\)

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